3.20 \(\int \frac {(b x+c x^2)^{3/2}}{x^6} \, dx\)

Optimal. Leaf size=48 \[ \frac {4 c \left (b x+c x^2\right )^{5/2}}{35 b^2 x^5}-\frac {2 \left (b x+c x^2\right )^{5/2}}{7 b x^6} \]

[Out]

-2/7*(c*x^2+b*x)^(5/2)/b/x^6+4/35*c*(c*x^2+b*x)^(5/2)/b^2/x^5

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Rubi [A]  time = 0.02, antiderivative size = 48, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {658, 650} \[ \frac {4 c \left (b x+c x^2\right )^{5/2}}{35 b^2 x^5}-\frac {2 \left (b x+c x^2\right )^{5/2}}{7 b x^6} \]

Antiderivative was successfully verified.

[In]

Int[(b*x + c*x^2)^(3/2)/x^6,x]

[Out]

(-2*(b*x + c*x^2)^(5/2))/(7*b*x^6) + (4*c*(b*x + c*x^2)^(5/2))/(35*b^2*x^5)

Rule 650

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(d + e*x)^m*(a +
b*x + c*x^2)^(p + 1))/((p + 1)*(2*c*d - b*e)), x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c, 0] &&
EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] && EqQ[m + 2*p + 2, 0]

Rule 658

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> -Simp[(e*(d + e*x)^m*(a +
b*x + c*x^2)^(p + 1))/((m + p + 1)*(2*c*d - b*e)), x] + Dist[(c*Simplify[m + 2*p + 2])/((m + p + 1)*(2*c*d -
b*e)), Int[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && NeQ[b^2 - 4*a*c
, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] &&  !IntegerQ[p] && ILtQ[Simplify[m + 2*p + 2], 0]

Rubi steps

\begin {align*} \int \frac {\left (b x+c x^2\right )^{3/2}}{x^6} \, dx &=-\frac {2 \left (b x+c x^2\right )^{5/2}}{7 b x^6}-\frac {(2 c) \int \frac {\left (b x+c x^2\right )^{3/2}}{x^5} \, dx}{7 b}\\ &=-\frac {2 \left (b x+c x^2\right )^{5/2}}{7 b x^6}+\frac {4 c \left (b x+c x^2\right )^{5/2}}{35 b^2 x^5}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 29, normalized size = 0.60 \[ \frac {2 (x (b+c x))^{5/2} (2 c x-5 b)}{35 b^2 x^6} \]

Antiderivative was successfully verified.

[In]

Integrate[(b*x + c*x^2)^(3/2)/x^6,x]

[Out]

(2*(x*(b + c*x))^(5/2)*(-5*b + 2*c*x))/(35*b^2*x^6)

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fricas [A]  time = 0.98, size = 49, normalized size = 1.02 \[ \frac {2 \, {\left (2 \, c^{3} x^{3} - b c^{2} x^{2} - 8 \, b^{2} c x - 5 \, b^{3}\right )} \sqrt {c x^{2} + b x}}{35 \, b^{2} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^(3/2)/x^6,x, algorithm="fricas")

[Out]

2/35*(2*c^3*x^3 - b*c^2*x^2 - 8*b^2*c*x - 5*b^3)*sqrt(c*x^2 + b*x)/(b^2*x^4)

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giac [B]  time = 0.33, size = 165, normalized size = 3.44 \[ \frac {2 \, {\left (35 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{5} c^{\frac {5}{2}} + 105 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{4} b c^{2} + 140 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{3} b^{2} c^{\frac {3}{2}} + 98 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{2} b^{3} c + 35 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )} b^{4} \sqrt {c} + 5 \, b^{5}\right )}}{35 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{7}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^(3/2)/x^6,x, algorithm="giac")

[Out]

2/35*(35*(sqrt(c)*x - sqrt(c*x^2 + b*x))^5*c^(5/2) + 105*(sqrt(c)*x - sqrt(c*x^2 + b*x))^4*b*c^2 + 140*(sqrt(c
)*x - sqrt(c*x^2 + b*x))^3*b^2*c^(3/2) + 98*(sqrt(c)*x - sqrt(c*x^2 + b*x))^2*b^3*c + 35*(sqrt(c)*x - sqrt(c*x
^2 + b*x))*b^4*sqrt(c) + 5*b^5)/(sqrt(c)*x - sqrt(c*x^2 + b*x))^7

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maple [A]  time = 0.05, size = 33, normalized size = 0.69 \[ -\frac {2 \left (c x +b \right ) \left (-2 c x +5 b \right ) \left (c \,x^{2}+b x \right )^{\frac {3}{2}}}{35 b^{2} x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+b*x)^(3/2)/x^6,x)

[Out]

-2/35*(c*x+b)*(-2*c*x+5*b)*(c*x^2+b*x)^(3/2)/b^2/x^5

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maxima [B]  time = 1.37, size = 95, normalized size = 1.98 \[ \frac {4 \, \sqrt {c x^{2} + b x} c^{3}}{35 \, b^{2} x} - \frac {2 \, \sqrt {c x^{2} + b x} c^{2}}{35 \, b x^{2}} + \frac {3 \, \sqrt {c x^{2} + b x} c}{70 \, x^{3}} + \frac {3 \, \sqrt {c x^{2} + b x} b}{14 \, x^{4}} - \frac {{\left (c x^{2} + b x\right )}^{\frac {3}{2}}}{2 \, x^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+b*x)^(3/2)/x^6,x, algorithm="maxima")

[Out]

4/35*sqrt(c*x^2 + b*x)*c^3/(b^2*x) - 2/35*sqrt(c*x^2 + b*x)*c^2/(b*x^2) + 3/70*sqrt(c*x^2 + b*x)*c/x^3 + 3/14*
sqrt(c*x^2 + b*x)*b/x^4 - 1/2*(c*x^2 + b*x)^(3/2)/x^5

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mupad [B]  time = 0.64, size = 79, normalized size = 1.65 \[ \frac {4\,c^3\,\sqrt {c\,x^2+b\,x}}{35\,b^2\,x}-\frac {16\,c\,\sqrt {c\,x^2+b\,x}}{35\,x^3}-\frac {2\,c^2\,\sqrt {c\,x^2+b\,x}}{35\,b\,x^2}-\frac {2\,b\,\sqrt {c\,x^2+b\,x}}{7\,x^4} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x + c*x^2)^(3/2)/x^6,x)

[Out]

(4*c^3*(b*x + c*x^2)^(1/2))/(35*b^2*x) - (16*c*(b*x + c*x^2)^(1/2))/(35*x^3) - (2*c^2*(b*x + c*x^2)^(1/2))/(35
*b*x^2) - (2*b*(b*x + c*x^2)^(1/2))/(7*x^4)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (x \left (b + c x\right )\right )^{\frac {3}{2}}}{x^{6}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+b*x)**(3/2)/x**6,x)

[Out]

Integral((x*(b + c*x))**(3/2)/x**6, x)

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